chore(quick-dev): drop the render.py success stderr line
The "rendered N files" progress line was pure diagnostic noise. The shim already tells the LLM to ignore stderr and follow the stdout instruction, so on success render.py now prints only the "read and follow ..." line. Co-Authored-By: Claude Opus 4.7 (1M context) <noreply@anthropic.com>
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@ -270,7 +270,6 @@ def main():
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if fname.endswith(".md"):
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if fname.endswith(".md"):
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os.remove(posixpath.join(out_dir, fname))
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os.remove(posixpath.join(out_dir, fname))
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count = 0
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for fname in sorted(os.listdir(script_dir)):
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for fname in sorted(os.listdir(script_dir)):
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if not fname.endswith(".md") or fname == "SKILL.md":
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if not fname.endswith(".md") or fname == "SKILL.md":
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continue
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continue
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@ -280,9 +279,7 @@ def main():
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content = fh.read()
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content = fh.read()
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with open(dst, "w", encoding="utf-8", newline="") as fh:
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with open(dst, "w", encoding="utf-8", newline="") as fh:
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fh.write(render_workflow(render_template(content, vars_), workflow))
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fh.write(render_workflow(render_template(content, vars_), workflow))
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count += 1
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print(f"render.py: rendered {count} files -> {out_dir}", file=sys.stderr)
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workflow_md = posixpath.join(out_dir, "workflow.md")
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workflow_md = posixpath.join(out_dir, "workflow.md")
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print(f"read and follow {workflow_md}")
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print(f"read and follow {workflow_md}")
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